bash: expecting number addition with +=. Not exactly sure if the operand is a number











up vote
2
down vote

favorite












I am trying to detect armstrong numbers with this code:



declare -i INPUT=$1


arr=($(fold -w1 <<< "$INPUT"))
for index in "${!arr[@]}"
do
armstrong_sum+=$((${arr[index]}**${#arr[@]}))
done


echo "$armstrong_sum"


Commands to run the code: ./armstrong_sum 9, armstrong_sum 10 and ./armstrong_sum 153



Output: 9, 10 and 112527



Expected output: 9, 1 and 153



An armstrong number is a number that is the sum of its own digits each raised to the power of number of digits



More importantly I want to be able to debug the script myself. Not exactly sure how one debugs in bash. Like get type of operand and see pause iteration at each step










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HarshvardhanSharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • your expected output doesnt make sense - by your own definition 153 should return 729
    – Steven Penny
    2 days ago












  • 1^3 + 5^3 + 3^3 = 153. This my expected output, i.e an armstrong number
    – HarshvardhanSharma
    2 days ago










  • Your second question (the bold part) already has an answer, easily found by searching: unix.stackexchange.com/questions/155551/…
    – JigglyNaga
    2 days ago















up vote
2
down vote

favorite












I am trying to detect armstrong numbers with this code:



declare -i INPUT=$1


arr=($(fold -w1 <<< "$INPUT"))
for index in "${!arr[@]}"
do
armstrong_sum+=$((${arr[index]}**${#arr[@]}))
done


echo "$armstrong_sum"


Commands to run the code: ./armstrong_sum 9, armstrong_sum 10 and ./armstrong_sum 153



Output: 9, 10 and 112527



Expected output: 9, 1 and 153



An armstrong number is a number that is the sum of its own digits each raised to the power of number of digits



More importantly I want to be able to debug the script myself. Not exactly sure how one debugs in bash. Like get type of operand and see pause iteration at each step










share|improve this question









New contributor




HarshvardhanSharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • your expected output doesnt make sense - by your own definition 153 should return 729
    – Steven Penny
    2 days ago












  • 1^3 + 5^3 + 3^3 = 153. This my expected output, i.e an armstrong number
    – HarshvardhanSharma
    2 days ago










  • Your second question (the bold part) already has an answer, easily found by searching: unix.stackexchange.com/questions/155551/…
    – JigglyNaga
    2 days ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I am trying to detect armstrong numbers with this code:



declare -i INPUT=$1


arr=($(fold -w1 <<< "$INPUT"))
for index in "${!arr[@]}"
do
armstrong_sum+=$((${arr[index]}**${#arr[@]}))
done


echo "$armstrong_sum"


Commands to run the code: ./armstrong_sum 9, armstrong_sum 10 and ./armstrong_sum 153



Output: 9, 10 and 112527



Expected output: 9, 1 and 153



An armstrong number is a number that is the sum of its own digits each raised to the power of number of digits



More importantly I want to be able to debug the script myself. Not exactly sure how one debugs in bash. Like get type of operand and see pause iteration at each step










share|improve this question









New contributor




HarshvardhanSharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I am trying to detect armstrong numbers with this code:



declare -i INPUT=$1


arr=($(fold -w1 <<< "$INPUT"))
for index in "${!arr[@]}"
do
armstrong_sum+=$((${arr[index]}**${#arr[@]}))
done


echo "$armstrong_sum"


Commands to run the code: ./armstrong_sum 9, armstrong_sum 10 and ./armstrong_sum 153



Output: 9, 10 and 112527



Expected output: 9, 1 and 153



An armstrong number is a number that is the sum of its own digits each raised to the power of number of digits



More importantly I want to be able to debug the script myself. Not exactly sure how one debugs in bash. Like get type of operand and see pause iteration at each step







bash






share|improve this question









New contributor




HarshvardhanSharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









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HarshvardhanSharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




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edited 2 days ago





















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asked Dec 7 at 3:30









HarshvardhanSharma

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New contributor





HarshvardhanSharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






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Check out our Code of Conduct.












  • your expected output doesnt make sense - by your own definition 153 should return 729
    – Steven Penny
    2 days ago












  • 1^3 + 5^3 + 3^3 = 153. This my expected output, i.e an armstrong number
    – HarshvardhanSharma
    2 days ago










  • Your second question (the bold part) already has an answer, easily found by searching: unix.stackexchange.com/questions/155551/…
    – JigglyNaga
    2 days ago


















  • your expected output doesnt make sense - by your own definition 153 should return 729
    – Steven Penny
    2 days ago












  • 1^3 + 5^3 + 3^3 = 153. This my expected output, i.e an armstrong number
    – HarshvardhanSharma
    2 days ago










  • Your second question (the bold part) already has an answer, easily found by searching: unix.stackexchange.com/questions/155551/…
    – JigglyNaga
    2 days ago
















your expected output doesnt make sense - by your own definition 153 should return 729
– Steven Penny
2 days ago






your expected output doesnt make sense - by your own definition 153 should return 729
– Steven Penny
2 days ago














1^3 + 5^3 + 3^3 = 153. This my expected output, i.e an armstrong number
– HarshvardhanSharma
2 days ago




1^3 + 5^3 + 3^3 = 153. This my expected output, i.e an armstrong number
– HarshvardhanSharma
2 days ago












Your second question (the bold part) already has an answer, easily found by searching: unix.stackexchange.com/questions/155551/…
– JigglyNaga
2 days ago




Your second question (the bold part) already has an answer, easily found by searching: unix.stackexchange.com/questions/155551/…
– JigglyNaga
2 days ago










2 Answers
2






active

oldest

votes

















up vote
2
down vote



accepted










As noted in man bash (emphasis mine)




When += is applied to a variable for which the
integer attribute has been set, value is evaluated as an arithmetic
expression and added to the variable's current value, which is also
evaluated.
When += is applied to an array variable using compound
assignment (see Arrays below), the variable's value is not unset (as it
is when using =), and new values are appended to the array beginning at
one greater than the array's maximum index (for indexed arrays) or
added as additional key-value pairs in an associative array. When
applied to a string-valued variable, value is expanded and appended to
the variable's value.




You are clearly getting the latter, i.e.



1 + 125 + 27 = 112527


So you have a couple of options - either declare armstrong_sum as integer



#!/bin/bash

declare -i INPUT=$1
declare -i armstrong_sum=0

arr=($(fold -w1 <<< "$INPUT"))
for index in "${!arr[@]}"
do
armstrong_sum+=$(( ${arr[index]}**${#arr[@]} ))
done


echo "$armstrong_sum"


or ensure arithmetic evaluation by surrounding the whole expression in (( and )) i.e.



(( armstrong_sum += ${arr[index]}**${#arr[@]} ))





share|improve this answer




























    up vote
    0
    down vote













    Use https://www.shellcheck.net (I use it as syntactic vim plugin making a crude IDE)



    I'd go with this;



    #!/bin/bash

    P="$(echo -n "$1" | wc -c)"
    SUM=0;
    for X in $(echo "$1" | fold -w 1) ; do
    SUM=$(echo "$SUM+($X^$P)" | bc );
    done
    echo "$SUM"


    It's not "pure" bash but I find the power of bash is the wide selection of tools, and prioritizing legibility.



    for stack traces if you add the following to the top of all your scripts it will inform you of errors;



    set -e
    trap 'echo "ERROR: $BASH_SOURCE:$LINENO $BASH_COMMAND" >&2' ERR


    it will stop the script on the error line, make output like



    test.sh: line 7: no: command not found
    ERROR: test.sh:7 no + 5


    instead of (potentially silently) ignoring errors.
    Use -x for debugging;



    bash -x armstrong.sh 222
    ++ echo -n 222
    ++ wc -c
    + P=3
    + SUM=0
    ++ fold -w 1
    ++ echo 222
    + for X in $(echo "$1" | fold -w 1)
    ++ echo '0+(2^3)'
    ++ bc
    + SUM=8
    + for X in $(echo "$1" | fold -w 1)
    ++ echo '8+(2^3)'
    ++ bc
    + SUM=16
    + for X in $(echo "$1" | fold -w 1)
    ++ echo '16+(2^3)'
    ++ bc
    + SUM=24
    + echo 24
    24





    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      2
      down vote



      accepted










      As noted in man bash (emphasis mine)




      When += is applied to a variable for which the
      integer attribute has been set, value is evaluated as an arithmetic
      expression and added to the variable's current value, which is also
      evaluated.
      When += is applied to an array variable using compound
      assignment (see Arrays below), the variable's value is not unset (as it
      is when using =), and new values are appended to the array beginning at
      one greater than the array's maximum index (for indexed arrays) or
      added as additional key-value pairs in an associative array. When
      applied to a string-valued variable, value is expanded and appended to
      the variable's value.




      You are clearly getting the latter, i.e.



      1 + 125 + 27 = 112527


      So you have a couple of options - either declare armstrong_sum as integer



      #!/bin/bash

      declare -i INPUT=$1
      declare -i armstrong_sum=0

      arr=($(fold -w1 <<< "$INPUT"))
      for index in "${!arr[@]}"
      do
      armstrong_sum+=$(( ${arr[index]}**${#arr[@]} ))
      done


      echo "$armstrong_sum"


      or ensure arithmetic evaluation by surrounding the whole expression in (( and )) i.e.



      (( armstrong_sum += ${arr[index]}**${#arr[@]} ))





      share|improve this answer

























        up vote
        2
        down vote



        accepted










        As noted in man bash (emphasis mine)




        When += is applied to a variable for which the
        integer attribute has been set, value is evaluated as an arithmetic
        expression and added to the variable's current value, which is also
        evaluated.
        When += is applied to an array variable using compound
        assignment (see Arrays below), the variable's value is not unset (as it
        is when using =), and new values are appended to the array beginning at
        one greater than the array's maximum index (for indexed arrays) or
        added as additional key-value pairs in an associative array. When
        applied to a string-valued variable, value is expanded and appended to
        the variable's value.




        You are clearly getting the latter, i.e.



        1 + 125 + 27 = 112527


        So you have a couple of options - either declare armstrong_sum as integer



        #!/bin/bash

        declare -i INPUT=$1
        declare -i armstrong_sum=0

        arr=($(fold -w1 <<< "$INPUT"))
        for index in "${!arr[@]}"
        do
        armstrong_sum+=$(( ${arr[index]}**${#arr[@]} ))
        done


        echo "$armstrong_sum"


        or ensure arithmetic evaluation by surrounding the whole expression in (( and )) i.e.



        (( armstrong_sum += ${arr[index]}**${#arr[@]} ))





        share|improve this answer























          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          As noted in man bash (emphasis mine)




          When += is applied to a variable for which the
          integer attribute has been set, value is evaluated as an arithmetic
          expression and added to the variable's current value, which is also
          evaluated.
          When += is applied to an array variable using compound
          assignment (see Arrays below), the variable's value is not unset (as it
          is when using =), and new values are appended to the array beginning at
          one greater than the array's maximum index (for indexed arrays) or
          added as additional key-value pairs in an associative array. When
          applied to a string-valued variable, value is expanded and appended to
          the variable's value.




          You are clearly getting the latter, i.e.



          1 + 125 + 27 = 112527


          So you have a couple of options - either declare armstrong_sum as integer



          #!/bin/bash

          declare -i INPUT=$1
          declare -i armstrong_sum=0

          arr=($(fold -w1 <<< "$INPUT"))
          for index in "${!arr[@]}"
          do
          armstrong_sum+=$(( ${arr[index]}**${#arr[@]} ))
          done


          echo "$armstrong_sum"


          or ensure arithmetic evaluation by surrounding the whole expression in (( and )) i.e.



          (( armstrong_sum += ${arr[index]}**${#arr[@]} ))





          share|improve this answer












          As noted in man bash (emphasis mine)




          When += is applied to a variable for which the
          integer attribute has been set, value is evaluated as an arithmetic
          expression and added to the variable's current value, which is also
          evaluated.
          When += is applied to an array variable using compound
          assignment (see Arrays below), the variable's value is not unset (as it
          is when using =), and new values are appended to the array beginning at
          one greater than the array's maximum index (for indexed arrays) or
          added as additional key-value pairs in an associative array. When
          applied to a string-valued variable, value is expanded and appended to
          the variable's value.




          You are clearly getting the latter, i.e.



          1 + 125 + 27 = 112527


          So you have a couple of options - either declare armstrong_sum as integer



          #!/bin/bash

          declare -i INPUT=$1
          declare -i armstrong_sum=0

          arr=($(fold -w1 <<< "$INPUT"))
          for index in "${!arr[@]}"
          do
          armstrong_sum+=$(( ${arr[index]}**${#arr[@]} ))
          done


          echo "$armstrong_sum"


          or ensure arithmetic evaluation by surrounding the whole expression in (( and )) i.e.



          (( armstrong_sum += ${arr[index]}**${#arr[@]} ))






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 days ago









          steeldriver

          33.9k34983




          33.9k34983
























              up vote
              0
              down vote













              Use https://www.shellcheck.net (I use it as syntactic vim plugin making a crude IDE)



              I'd go with this;



              #!/bin/bash

              P="$(echo -n "$1" | wc -c)"
              SUM=0;
              for X in $(echo "$1" | fold -w 1) ; do
              SUM=$(echo "$SUM+($X^$P)" | bc );
              done
              echo "$SUM"


              It's not "pure" bash but I find the power of bash is the wide selection of tools, and prioritizing legibility.



              for stack traces if you add the following to the top of all your scripts it will inform you of errors;



              set -e
              trap 'echo "ERROR: $BASH_SOURCE:$LINENO $BASH_COMMAND" >&2' ERR


              it will stop the script on the error line, make output like



              test.sh: line 7: no: command not found
              ERROR: test.sh:7 no + 5


              instead of (potentially silently) ignoring errors.
              Use -x for debugging;



              bash -x armstrong.sh 222
              ++ echo -n 222
              ++ wc -c
              + P=3
              + SUM=0
              ++ fold -w 1
              ++ echo 222
              + for X in $(echo "$1" | fold -w 1)
              ++ echo '0+(2^3)'
              ++ bc
              + SUM=8
              + for X in $(echo "$1" | fold -w 1)
              ++ echo '8+(2^3)'
              ++ bc
              + SUM=16
              + for X in $(echo "$1" | fold -w 1)
              ++ echo '16+(2^3)'
              ++ bc
              + SUM=24
              + echo 24
              24





              share|improve this answer



























                up vote
                0
                down vote













                Use https://www.shellcheck.net (I use it as syntactic vim plugin making a crude IDE)



                I'd go with this;



                #!/bin/bash

                P="$(echo -n "$1" | wc -c)"
                SUM=0;
                for X in $(echo "$1" | fold -w 1) ; do
                SUM=$(echo "$SUM+($X^$P)" | bc );
                done
                echo "$SUM"


                It's not "pure" bash but I find the power of bash is the wide selection of tools, and prioritizing legibility.



                for stack traces if you add the following to the top of all your scripts it will inform you of errors;



                set -e
                trap 'echo "ERROR: $BASH_SOURCE:$LINENO $BASH_COMMAND" >&2' ERR


                it will stop the script on the error line, make output like



                test.sh: line 7: no: command not found
                ERROR: test.sh:7 no + 5


                instead of (potentially silently) ignoring errors.
                Use -x for debugging;



                bash -x armstrong.sh 222
                ++ echo -n 222
                ++ wc -c
                + P=3
                + SUM=0
                ++ fold -w 1
                ++ echo 222
                + for X in $(echo "$1" | fold -w 1)
                ++ echo '0+(2^3)'
                ++ bc
                + SUM=8
                + for X in $(echo "$1" | fold -w 1)
                ++ echo '8+(2^3)'
                ++ bc
                + SUM=16
                + for X in $(echo "$1" | fold -w 1)
                ++ echo '16+(2^3)'
                ++ bc
                + SUM=24
                + echo 24
                24





                share|improve this answer

























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  Use https://www.shellcheck.net (I use it as syntactic vim plugin making a crude IDE)



                  I'd go with this;



                  #!/bin/bash

                  P="$(echo -n "$1" | wc -c)"
                  SUM=0;
                  for X in $(echo "$1" | fold -w 1) ; do
                  SUM=$(echo "$SUM+($X^$P)" | bc );
                  done
                  echo "$SUM"


                  It's not "pure" bash but I find the power of bash is the wide selection of tools, and prioritizing legibility.



                  for stack traces if you add the following to the top of all your scripts it will inform you of errors;



                  set -e
                  trap 'echo "ERROR: $BASH_SOURCE:$LINENO $BASH_COMMAND" >&2' ERR


                  it will stop the script on the error line, make output like



                  test.sh: line 7: no: command not found
                  ERROR: test.sh:7 no + 5


                  instead of (potentially silently) ignoring errors.
                  Use -x for debugging;



                  bash -x armstrong.sh 222
                  ++ echo -n 222
                  ++ wc -c
                  + P=3
                  + SUM=0
                  ++ fold -w 1
                  ++ echo 222
                  + for X in $(echo "$1" | fold -w 1)
                  ++ echo '0+(2^3)'
                  ++ bc
                  + SUM=8
                  + for X in $(echo "$1" | fold -w 1)
                  ++ echo '8+(2^3)'
                  ++ bc
                  + SUM=16
                  + for X in $(echo "$1" | fold -w 1)
                  ++ echo '16+(2^3)'
                  ++ bc
                  + SUM=24
                  + echo 24
                  24





                  share|improve this answer














                  Use https://www.shellcheck.net (I use it as syntactic vim plugin making a crude IDE)



                  I'd go with this;



                  #!/bin/bash

                  P="$(echo -n "$1" | wc -c)"
                  SUM=0;
                  for X in $(echo "$1" | fold -w 1) ; do
                  SUM=$(echo "$SUM+($X^$P)" | bc );
                  done
                  echo "$SUM"


                  It's not "pure" bash but I find the power of bash is the wide selection of tools, and prioritizing legibility.



                  for stack traces if you add the following to the top of all your scripts it will inform you of errors;



                  set -e
                  trap 'echo "ERROR: $BASH_SOURCE:$LINENO $BASH_COMMAND" >&2' ERR


                  it will stop the script on the error line, make output like



                  test.sh: line 7: no: command not found
                  ERROR: test.sh:7 no + 5


                  instead of (potentially silently) ignoring errors.
                  Use -x for debugging;



                  bash -x armstrong.sh 222
                  ++ echo -n 222
                  ++ wc -c
                  + P=3
                  + SUM=0
                  ++ fold -w 1
                  ++ echo 222
                  + for X in $(echo "$1" | fold -w 1)
                  ++ echo '0+(2^3)'
                  ++ bc
                  + SUM=8
                  + for X in $(echo "$1" | fold -w 1)
                  ++ echo '8+(2^3)'
                  ++ bc
                  + SUM=16
                  + for X in $(echo "$1" | fold -w 1)
                  ++ echo '16+(2^3)'
                  ++ bc
                  + SUM=24
                  + echo 24
                  24






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 2 days ago

























                  answered 2 days ago









                  user1133275

                  2,750415




                  2,750415






















                      HarshvardhanSharma is a new contributor. Be nice, and check out our Code of Conduct.










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