AUC ROC in keras is different when using tensorflow or scikit functions.
Two solutions for using AUC-ROC to train keras models, proposed here worked for me. But using tensorflow or scikit rocauc functions I get different results.
def auc(y_true, y_pred):
auc = tf.metrics.auc(y_true, y_pred)[1]
K.get_session().run(tf.local_variables_initializer())
return auc
and
def auc(y_true, y_pred):
return tf.py_func(roc_auc_score, (y_true, y_pred), tf.double)
Based on the history, it looks like both are being applied to train and validation.
When I plot history metrics, tensorflow curve looks very smoothed compared to scikit.
Shouldn't I get about the same results using both functions?
deep-learning keras scikit-learn performance
asked 3 hours ago
aerijman
164
add a comment |
Two solutions for using AUC-ROC to train keras models, proposed here worked for me. But using tensorflow or scikit rocauc functions I get different results.
def auc(y_true, y_pred):
auc = tf.metrics.auc(y_true, y_pred)[1]
K.get_session().run(tf.local_variables_initializer())
return auc
and
def auc(y_true, y_pred):
return tf.py_func(roc_auc_score, (y_true, y_pred), tf.double)
Based on the history, it looks like both are being applied to train and validation.
When I plot history metrics, tensorflow curve looks very smoothed compared to scikit.
Shouldn't I get about the same results using both functions?
deep-learning keras scikit-learn performance
asked 3 hours ago
aerijman
164
add a comment |
Two solutions for using AUC-ROC to train keras models, proposed here worked for me. But using tensorflow or scikit rocauc functions I get different results.
def auc(y_true, y_pred):
auc = tf.metrics.auc(y_true, y_pred)[1]
K.get_session().run(tf.local_variables_initializer())
return auc
and
def auc(y_true, y_pred):
return tf.py_func(roc_auc_score, (y_true, y_pred), tf.double)
Based on the history, it looks like both are being applied to train and validation.
When I plot history metrics, tensorflow curve looks very smoothed compared to scikit.
Shouldn't I get about the same results using both functions?
deep-learning keras scikit-learn performance
asked 3 hours ago
aerijman
164
Two solutions for using AUC-ROC to train keras models, proposed here worked for me. But using tensorflow or scikit rocauc functions I get different results.
def auc(y_true, y_pred):
auc = tf.metrics.auc(y_true, y_pred)[1]
K.get_session().run(tf.local_variables_initializer())
return auc
and
def auc(y_true, y_pred):
return tf.py_func(roc_auc_score, (y_true, y_pred), tf.double)
Based on the history, it looks like both are being applied to train and validation.
When I plot history metrics, tensorflow curve looks very smoothed compared to scikit.
Shouldn't I get about the same results using both functions?
deep-learning keras scikit-learn performance
deep-learning keras scikit-learn performance
asked 3 hours ago
aerijman
164
asked 3 hours ago
aerijman
164
asked 3 hours ago
aerijman
164
asked 3 hours ago
aerijman
164
asked 3 hours ago
aerijman
164
164
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
No, you shouldn't have the same numbers. All depends on the additional parameters:
tf.metrics.auc(
labels,
predictions,
weights=None,
num_thresholds=200,
metrics_collections=None,
updates_collections=None,
curve='ROC',
name=None,
summation_method='trapezoidal'
)
This means that this curve will have 200 points, so very smooth.
sklearn version doesn't have this kind of parameters:
roc_auc_score(y_true, y_score, average=’macro’, sample_weight=None, max_fpr=None)
The number of outputs depends on the curve and the number of points if I remember properly.
answered 3 hours ago
Matthieu Brucher
45813
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
No, you shouldn't have the same numbers. All depends on the additional parameters:
tf.metrics.auc(
labels,
predictions,
weights=None,
num_thresholds=200,
metrics_collections=None,
updates_collections=None,
curve='ROC',
name=None,
summation_method='trapezoidal'
)
This means that this curve will have 200 points, so very smooth.
sklearn version doesn't have this kind of parameters:
roc_auc_score(y_true, y_score, average=’macro’, sample_weight=None, max_fpr=None)
The number of outputs depends on the curve and the number of points if I remember properly.
answered 3 hours ago
Matthieu Brucher
45813
add a comment |
No, you shouldn't have the same numbers. All depends on the additional parameters:
tf.metrics.auc(
labels,
predictions,
weights=None,
num_thresholds=200,
metrics_collections=None,
updates_collections=None,
curve='ROC',
name=None,
summation_method='trapezoidal'
)
This means that this curve will have 200 points, so very smooth.
sklearn version doesn't have this kind of parameters:
roc_auc_score(y_true, y_score, average=’macro’, sample_weight=None, max_fpr=None)
The number of outputs depends on the curve and the number of points if I remember properly.
answered 3 hours ago
Matthieu Brucher
45813
add a comment |
No, you shouldn't have the same numbers. All depends on the additional parameters:
tf.metrics.auc(
labels,
predictions,
weights=None,
num_thresholds=200,
metrics_collections=None,
updates_collections=None,
curve='ROC',
name=None,
summation_method='trapezoidal'
)
This means that this curve will have 200 points, so very smooth.
sklearn version doesn't have this kind of parameters:
roc_auc_score(y_true, y_score, average=’macro’, sample_weight=None, max_fpr=None)
The number of outputs depends on the curve and the number of points if I remember properly.
answered 3 hours ago
Matthieu Brucher
45813
No, you shouldn't have the same numbers. All depends on the additional parameters:
tf.metrics.auc(
labels,
predictions,
weights=None,
num_thresholds=200,
metrics_collections=None,
updates_collections=None,
curve='ROC',
name=None,
summation_method='trapezoidal'
)
This means that this curve will have 200 points, so very smooth.
sklearn version doesn't have this kind of parameters:
roc_auc_score(y_true, y_score, average=’macro’, sample_weight=None, max_fpr=None)
The number of outputs depends on the curve and the number of points if I remember properly.
answered 3 hours ago
Matthieu Brucher
45813
answered 3 hours ago
Matthieu Brucher
45813
answered 3 hours ago
Matthieu Brucher
45813
answered 3 hours ago
Matthieu Brucher
45813
45813
add a comment |
add a comment |
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