What does this command with two filenames in it mean?












-1















./getProductAccess.sh access-2014-09-04.log



Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.






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    -1















    ./getProductAccess.sh access-2014-09-04.log



    Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.






    linux shell-script shell







    share|improve this question







    New contributor




    Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      -1












      -1








      -1








      ./getProductAccess.sh access-2014-09-04.log



      Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.






      linux shell-script shell







      share|improve this question







      New contributor




      Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      ./getProductAccess.sh access-2014-09-04.log



      Normally there is only 1 file behind ./. Now there are two. It seems the second one is to provide input, but what should write in the first one to get the input? Because read doesn't work.






      linux shell-script shell




      linux shell-script shell






      share|improve this question







      New contributor




      Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







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      Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this question




      share|improve this question






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      asked 16 mins ago









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      Victor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          This really is beginners 101.



          ./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.



          If you're writing the program you could reference that first argument as "$1".






          share|improve this answer































            0














            There is no need to use read you can use $1.



            So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.



            $0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...






            share|improve this answer

























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              0














              This really is beginners 101.



              ./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.



              If you're writing the program you could reference that first argument as "$1".






              share|improve this answer




























                0














                This really is beginners 101.



                ./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.



                If you're writing the program you could reference that first argument as "$1".






                share|improve this answer


























                  0












                  0








                  0







                  This really is beginners 101.



                  ./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.



                  If you're writing the program you could reference that first argument as "$1".






                  share|improve this answer













                  This really is beginners 101.



                  ./getProductAccess.sh is the program to run (in the current directory) and access-2014-09-04.log is an argument supplied to that program.



                  If you're writing the program you could reference that first argument as "$1".







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 11 mins ago









                  roaimaroaima

                  44.2k555119




                  44.2k555119

























                      0














                      There is no need to use read you can use $1.



                      So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.



                      $0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...






                      share|improve this answer






























                        0














                        There is no need to use read you can use $1.



                        So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.



                        $0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...






                        share|improve this answer




























                          0












                          0








                          0







                          There is no need to use read you can use $1.



                          So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.



                          $0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...






                          share|improve this answer















                          There is no need to use read you can use $1.



                          So in your script if you will use echo "$1", then it will give output as access-2014-09-04.log.



                          $0 is the path(relative or absolute) of the file which you are executing. $1 is the first argument passed to file, $2 second and so on...







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 6 mins ago

























                          answered 13 mins ago









                          P_YadavP_Yadav

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