SED not removing last double quote from every line











up vote
0
down vote

favorite
1












I have a CSV that was exported with double quotes around every header and value and I need them gone but without removing double quotes that might actually exist as values. For example:



"HEADER1","HEADER2","HEADER3","HEADER4","HEADER5"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"


I can remove the first " from every line with the following



$ sed -i.bak 's/^"//g' $1


And I can remove all the ones in between with this:



$ sed -i.bak 's/","/,/g' $1


And finally I thought I could remove the last " in every line with this:



$ sed -i.bak 's/"$//g' $1


But it's not working. Could I accomplish this entire task in one line?



UPDATE
I used this website to paste my data for hidden characters and here was the results



enter image description here



It appears some of the comment may be accurate but I don't know what that means I need to change still. Also is there a a clean way to check if the CSV has these quotes before attempting to remove them? Perhaps even just qualifying that the first character is a quote?










share|improve this question









New contributor




Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 5




    Perhaps " is not really the last character on each line (either because of trailing whitespace, or even because of DOS CRLF line endings)?
    – steeldriver
    Dec 6 at 0:29






  • 1




    That actually works fine for me when I copy & paste your data into a file; I'll hazard a guess that your real data differs from what you showed us, and that there's either a space or some other non-printing character in the last position before the n ..
    – tink
    Dec 6 at 0:30










  • have you tried dos2unix ??
    – msp9011
    Dec 6 at 6:47















up vote
0
down vote

favorite
1












I have a CSV that was exported with double quotes around every header and value and I need them gone but without removing double quotes that might actually exist as values. For example:



"HEADER1","HEADER2","HEADER3","HEADER4","HEADER5"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"


I can remove the first " from every line with the following



$ sed -i.bak 's/^"//g' $1


And I can remove all the ones in between with this:



$ sed -i.bak 's/","/,/g' $1


And finally I thought I could remove the last " in every line with this:



$ sed -i.bak 's/"$//g' $1


But it's not working. Could I accomplish this entire task in one line?



UPDATE
I used this website to paste my data for hidden characters and here was the results



enter image description here



It appears some of the comment may be accurate but I don't know what that means I need to change still. Also is there a a clean way to check if the CSV has these quotes before attempting to remove them? Perhaps even just qualifying that the first character is a quote?










share|improve this question









New contributor




Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 5




    Perhaps " is not really the last character on each line (either because of trailing whitespace, or even because of DOS CRLF line endings)?
    – steeldriver
    Dec 6 at 0:29






  • 1




    That actually works fine for me when I copy & paste your data into a file; I'll hazard a guess that your real data differs from what you showed us, and that there's either a space or some other non-printing character in the last position before the n ..
    – tink
    Dec 6 at 0:30










  • have you tried dos2unix ??
    – msp9011
    Dec 6 at 6:47













up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





I have a CSV that was exported with double quotes around every header and value and I need them gone but without removing double quotes that might actually exist as values. For example:



"HEADER1","HEADER2","HEADER3","HEADER4","HEADER5"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"


I can remove the first " from every line with the following



$ sed -i.bak 's/^"//g' $1


And I can remove all the ones in between with this:



$ sed -i.bak 's/","/,/g' $1


And finally I thought I could remove the last " in every line with this:



$ sed -i.bak 's/"$//g' $1


But it's not working. Could I accomplish this entire task in one line?



UPDATE
I used this website to paste my data for hidden characters and here was the results



enter image description here



It appears some of the comment may be accurate but I don't know what that means I need to change still. Also is there a a clean way to check if the CSV has these quotes before attempting to remove them? Perhaps even just qualifying that the first character is a quote?










share|improve this question









New contributor




Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I have a CSV that was exported with double quotes around every header and value and I need them gone but without removing double quotes that might actually exist as values. For example:



"HEADER1","HEADER2","HEADER3","HEADER4","HEADER5"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"
"SOME_ID_0X0","SOME_ID_1X2","false","Some blob value with "double quotes" inside of it"


I can remove the first " from every line with the following



$ sed -i.bak 's/^"//g' $1


And I can remove all the ones in between with this:



$ sed -i.bak 's/","/,/g' $1


And finally I thought I could remove the last " in every line with this:



$ sed -i.bak 's/"$//g' $1


But it's not working. Could I accomplish this entire task in one line?



UPDATE
I used this website to paste my data for hidden characters and here was the results



enter image description here



It appears some of the comment may be accurate but I don't know what that means I need to change still. Also is there a a clean way to check if the CSV has these quotes before attempting to remove them? Perhaps even just qualifying that the first character is a quote?







sed csv csv-simple






share|improve this question









New contributor




Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited yesterday









Rui F Ribeiro

38.4k1479128




38.4k1479128






New contributor




Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Dec 6 at 0:20









Xtremefaith

1032




1032




New contributor




Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Xtremefaith is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 5




    Perhaps " is not really the last character on each line (either because of trailing whitespace, or even because of DOS CRLF line endings)?
    – steeldriver
    Dec 6 at 0:29






  • 1




    That actually works fine for me when I copy & paste your data into a file; I'll hazard a guess that your real data differs from what you showed us, and that there's either a space or some other non-printing character in the last position before the n ..
    – tink
    Dec 6 at 0:30










  • have you tried dos2unix ??
    – msp9011
    Dec 6 at 6:47














  • 5




    Perhaps " is not really the last character on each line (either because of trailing whitespace, or even because of DOS CRLF line endings)?
    – steeldriver
    Dec 6 at 0:29






  • 1




    That actually works fine for me when I copy & paste your data into a file; I'll hazard a guess that your real data differs from what you showed us, and that there's either a space or some other non-printing character in the last position before the n ..
    – tink
    Dec 6 at 0:30










  • have you tried dos2unix ??
    – msp9011
    Dec 6 at 6:47








5




5




Perhaps " is not really the last character on each line (either because of trailing whitespace, or even because of DOS CRLF line endings)?
– steeldriver
Dec 6 at 0:29




Perhaps " is not really the last character on each line (either because of trailing whitespace, or even because of DOS CRLF line endings)?
– steeldriver
Dec 6 at 0:29




1




1




That actually works fine for me when I copy & paste your data into a file; I'll hazard a guess that your real data differs from what you showed us, and that there's either a space or some other non-printing character in the last position before the n ..
– tink
Dec 6 at 0:30




That actually works fine for me when I copy & paste your data into a file; I'll hazard a guess that your real data differs from what you showed us, and that there's either a space or some other non-printing character in the last position before the n ..
– tink
Dec 6 at 0:30












have you tried dos2unix ??
– msp9011
Dec 6 at 6:47




have you tried dos2unix ??
– msp9011
Dec 6 at 6:47










2 Answers
2






active

oldest

votes

















up vote
2
down vote



accepted










Use dos2unix to convert DOS to UNIX text file format



dos2unix $1


You could combine all 3 sed as:



 sed -i 's/^"//g;s/","/,/g;s/"$//g' $1

SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it


Using AWK :



awk -F ',' -v OFS=',' '{for (i=1;i<=NF;i++) sub(/^"/,"",$i) sub (/"$/,"",$i); print $0}' 1$

HEADER1,HEADER2,HEADER3,HEADER4,HEADER5
SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it




  • sub(/^"/,"",$i) removes the " at start of each field.


  • sub(/"$/,"",$i) removes the " at end of each field.






share|improve this answer



















  • 1




    You can do "dos2unix" in sed: sed 's/r$//' file, so removing trailing quote is sed 's/r$//; s/"$//' -- should work even if file has unix format.
    – glenn jackman
    2 days ago


















up vote
0
down vote













Running 'sed -i.bak' 3 times will overwrite the backup file each time, so at the end you won't have the original file in your backup file. You should use '-i.bak' once and '-i' the rest of the times.



sed -i.bak -e 's/^"//' -e 's/","/,/g' -e 's/"$//' a.txt



Use -e <expression> to use multiple sed expressions.



You don't need the 'g' for the first and last lines, because you're only doing one replacement.



I don't know why the last one isn't working for you, because it's correct as written. Either a typo on your end or maybe an issue with an environment variable or locale.



Another way to do it is search for




  1. a quote

  2. text that isn't a quote

  3. a quote

  4. either a comma or end-of-line


and keep and restore the 2nd and 4th parts. Like this:



sed 's/"([^"]*)"([,$])/12/g' a.txt



The ( and ) store the 2nd and 4th parts, and they're restored in the replace portion.






share|improve this answer























    Your Answer








    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "106"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });






    Xtremefaith is a new contributor. Be nice, and check out our Code of Conduct.










    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f486259%2fsed-not-removing-last-double-quote-from-every-line%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote



    accepted










    Use dos2unix to convert DOS to UNIX text file format



    dos2unix $1


    You could combine all 3 sed as:



     sed -i 's/^"//g;s/","/,/g;s/"$//g' $1

    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it


    Using AWK :



    awk -F ',' -v OFS=',' '{for (i=1;i<=NF;i++) sub(/^"/,"",$i) sub (/"$/,"",$i); print $0}' 1$

    HEADER1,HEADER2,HEADER3,HEADER4,HEADER5
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it




    • sub(/^"/,"",$i) removes the " at start of each field.


    • sub(/"$/,"",$i) removes the " at end of each field.






    share|improve this answer



















    • 1




      You can do "dos2unix" in sed: sed 's/r$//' file, so removing trailing quote is sed 's/r$//; s/"$//' -- should work even if file has unix format.
      – glenn jackman
      2 days ago















    up vote
    2
    down vote



    accepted










    Use dos2unix to convert DOS to UNIX text file format



    dos2unix $1


    You could combine all 3 sed as:



     sed -i 's/^"//g;s/","/,/g;s/"$//g' $1

    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it


    Using AWK :



    awk -F ',' -v OFS=',' '{for (i=1;i<=NF;i++) sub(/^"/,"",$i) sub (/"$/,"",$i); print $0}' 1$

    HEADER1,HEADER2,HEADER3,HEADER4,HEADER5
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it




    • sub(/^"/,"",$i) removes the " at start of each field.


    • sub(/"$/,"",$i) removes the " at end of each field.






    share|improve this answer



















    • 1




      You can do "dos2unix" in sed: sed 's/r$//' file, so removing trailing quote is sed 's/r$//; s/"$//' -- should work even if file has unix format.
      – glenn jackman
      2 days ago













    up vote
    2
    down vote



    accepted







    up vote
    2
    down vote



    accepted






    Use dos2unix to convert DOS to UNIX text file format



    dos2unix $1


    You could combine all 3 sed as:



     sed -i 's/^"//g;s/","/,/g;s/"$//g' $1

    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it


    Using AWK :



    awk -F ',' -v OFS=',' '{for (i=1;i<=NF;i++) sub(/^"/,"",$i) sub (/"$/,"",$i); print $0}' 1$

    HEADER1,HEADER2,HEADER3,HEADER4,HEADER5
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it




    • sub(/^"/,"",$i) removes the " at start of each field.


    • sub(/"$/,"",$i) removes the " at end of each field.






    share|improve this answer














    Use dos2unix to convert DOS to UNIX text file format



    dos2unix $1


    You could combine all 3 sed as:



     sed -i 's/^"//g;s/","/,/g;s/"$//g' $1

    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it


    Using AWK :



    awk -F ',' -v OFS=',' '{for (i=1;i<=NF;i++) sub(/^"/,"",$i) sub (/"$/,"",$i); print $0}' 1$

    HEADER1,HEADER2,HEADER3,HEADER4,HEADER5
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it
    SOME_ID_0X0,SOME_ID_1X2,false,Some blob value with "double quotes" inside of it




    • sub(/^"/,"",$i) removes the " at start of each field.


    • sub(/"$/,"",$i) removes the " at end of each field.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Dec 6 at 6:52

























    answered Dec 6 at 5:23









    msp9011

    3,64043863




    3,64043863








    • 1




      You can do "dos2unix" in sed: sed 's/r$//' file, so removing trailing quote is sed 's/r$//; s/"$//' -- should work even if file has unix format.
      – glenn jackman
      2 days ago














    • 1




      You can do "dos2unix" in sed: sed 's/r$//' file, so removing trailing quote is sed 's/r$//; s/"$//' -- should work even if file has unix format.
      – glenn jackman
      2 days ago








    1




    1




    You can do "dos2unix" in sed: sed 's/r$//' file, so removing trailing quote is sed 's/r$//; s/"$//' -- should work even if file has unix format.
    – glenn jackman
    2 days ago




    You can do "dos2unix" in sed: sed 's/r$//' file, so removing trailing quote is sed 's/r$//; s/"$//' -- should work even if file has unix format.
    – glenn jackman
    2 days ago












    up vote
    0
    down vote













    Running 'sed -i.bak' 3 times will overwrite the backup file each time, so at the end you won't have the original file in your backup file. You should use '-i.bak' once and '-i' the rest of the times.



    sed -i.bak -e 's/^"//' -e 's/","/,/g' -e 's/"$//' a.txt



    Use -e <expression> to use multiple sed expressions.



    You don't need the 'g' for the first and last lines, because you're only doing one replacement.



    I don't know why the last one isn't working for you, because it's correct as written. Either a typo on your end or maybe an issue with an environment variable or locale.



    Another way to do it is search for




    1. a quote

    2. text that isn't a quote

    3. a quote

    4. either a comma or end-of-line


    and keep and restore the 2nd and 4th parts. Like this:



    sed 's/"([^"]*)"([,$])/12/g' a.txt



    The ( and ) store the 2nd and 4th parts, and they're restored in the replace portion.






    share|improve this answer



























      up vote
      0
      down vote













      Running 'sed -i.bak' 3 times will overwrite the backup file each time, so at the end you won't have the original file in your backup file. You should use '-i.bak' once and '-i' the rest of the times.



      sed -i.bak -e 's/^"//' -e 's/","/,/g' -e 's/"$//' a.txt



      Use -e <expression> to use multiple sed expressions.



      You don't need the 'g' for the first and last lines, because you're only doing one replacement.



      I don't know why the last one isn't working for you, because it's correct as written. Either a typo on your end or maybe an issue with an environment variable or locale.



      Another way to do it is search for




      1. a quote

      2. text that isn't a quote

      3. a quote

      4. either a comma or end-of-line


      and keep and restore the 2nd and 4th parts. Like this:



      sed 's/"([^"]*)"([,$])/12/g' a.txt



      The ( and ) store the 2nd and 4th parts, and they're restored in the replace portion.






      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        Running 'sed -i.bak' 3 times will overwrite the backup file each time, so at the end you won't have the original file in your backup file. You should use '-i.bak' once and '-i' the rest of the times.



        sed -i.bak -e 's/^"//' -e 's/","/,/g' -e 's/"$//' a.txt



        Use -e <expression> to use multiple sed expressions.



        You don't need the 'g' for the first and last lines, because you're only doing one replacement.



        I don't know why the last one isn't working for you, because it's correct as written. Either a typo on your end or maybe an issue with an environment variable or locale.



        Another way to do it is search for




        1. a quote

        2. text that isn't a quote

        3. a quote

        4. either a comma or end-of-line


        and keep and restore the 2nd and 4th parts. Like this:



        sed 's/"([^"]*)"([,$])/12/g' a.txt



        The ( and ) store the 2nd and 4th parts, and they're restored in the replace portion.






        share|improve this answer














        Running 'sed -i.bak' 3 times will overwrite the backup file each time, so at the end you won't have the original file in your backup file. You should use '-i.bak' once and '-i' the rest of the times.



        sed -i.bak -e 's/^"//' -e 's/","/,/g' -e 's/"$//' a.txt



        Use -e <expression> to use multiple sed expressions.



        You don't need the 'g' for the first and last lines, because you're only doing one replacement.



        I don't know why the last one isn't working for you, because it's correct as written. Either a typo on your end or maybe an issue with an environment variable or locale.



        Another way to do it is search for




        1. a quote

        2. text that isn't a quote

        3. a quote

        4. either a comma or end-of-line


        and keep and restore the 2nd and 4th parts. Like this:



        sed 's/"([^"]*)"([,$])/12/g' a.txt



        The ( and ) store the 2nd and 4th parts, and they're restored in the replace portion.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Dec 6 at 0:33

























        answered Dec 6 at 0:26









        drewbenn

        5,14251836




        5,14251836






















            Xtremefaith is a new contributor. Be nice, and check out our Code of Conduct.










            draft saved

            draft discarded


















            Xtremefaith is a new contributor. Be nice, and check out our Code of Conduct.













            Xtremefaith is a new contributor. Be nice, and check out our Code of Conduct.












            Xtremefaith is a new contributor. Be nice, and check out our Code of Conduct.
















            Thanks for contributing an answer to Unix & Linux Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f486259%2fsed-not-removing-last-double-quote-from-every-line%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            サソリ

            広島県道265号伴広島線

            Accessing regular linux commands in Huawei's Dopra Linux