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How can i delete a line if it is longer than e.g.: 2048 chars?

sed '/^.{2048}./d' input.txt > output.txt

Here's a solution which deletes lines that has 2049 or more characters:

sed -E '/^.{2049}/d' <file.in >file.out

Strictly speaking, the ^ anchor is not needed.

With awk, printing lines of length 2048 or shorter:

awk 'length <= 2048' <file.in >file.out

Something like this should work in Python.

of = open("orig")

nf = open("new",'w')

for line in of:         

    if len(line) < 2048:

        nf.write(line)

of.close()

nf.close()

perl -lne "length < 2048 && print" infile > outfile

The above answers do not work for me on Mac OS X 10.9.5.

The following code does work:

sed '/.{2048}/d'.

Although not asked, but provided for reference, the reverse can be achieved the following code:

sed '/.{2048}/!d'.

With gnu-sed, you may use the -r flag, to avoid typing the backslashes, and a comma, to define an open interval:

sed -r  "/.{2049,}/d" input.txt > output.txt

with:

• x{2049} meaning exactly 2049 xs


• x{2049,3072} meaning from 2049 to 3072 xs


• x{2049,} meaning at least 2049 xs


• x{,2049} meaning at most 2049 xs

For the intervals, to not match bigger patterns, you would need line anchors like

sed -r  "/^.{32,64}$/d" input.txt > output.txt